Question

Least count of a screw gauge is given by

• A. Pitch of Screw + Number of Head Scale Div.
• B. Pitch of Screw / Number of Head Scale Div.
• C. Both (a) and (b)
• D. None of these

Answer 1

Answer: (B)

Pitch of Screw / Number of Head Scale Div.

$\begin{array}{c}\text{A screw gauge of}100\text{division will move the capscale}\\ \text{along the main scale by}1/100\text{of}mm\text{-}0.0\text{I mm . This}\\ \text{is the minimum value up to which a screw gauge can}\\ \text{measure and is Known as its least count. OR it is}\\ \text{defined as the ratio between the pitch of the screw}\\ \text{and the number of divisions on the circular scale.}\end{array}$

Hence option B is correct