Least count of screw gauge is defined as :

\frac{d i s t a n c e m o v e d b y t h i m b l e o n m a i n s c a l e}{n u m b e r o f r o t a t i o n o f t h i m b l e}

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\frac{p i t c h o f t h e s c r e w}{n u m b e r o f c i r c u l a r s c a l e d i v i s i o n s o n h e a d s c a l e}

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\frac{n u m b e r o f r o t a t i o n o f t h i m b l e}{n u m b e r o f c i r c u l a r s c a l e d i v i s i o n s}

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None of the above

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Solution

The correct option is B $\frac{p i t c h o f t h e s c r e w}{n u m b e r o f c i r c u l a r s c a l e d i v i s i o n s o n h e a d s c a l e}$
Screw gauge is a more accurate measuring instrument than the vernier caliper. The least count of screw gauge is equal to the ratio of pitch of the screw to the number of the division on circular scale.
For example: Pitch of the screw $= 1$ $m m$
Number of circular scale division $= 100$
$∴$ Least count of screw gauge $= \frac{1 m m}{100} = 0.01$ $m m$

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