Least stable hydride is:

Stannane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Silane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Plumbane

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Germane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Plumbane
The stability order of hydrides of group $14$ element is given as:
$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$
Among these, methane $(C H_{4})$ is versatile, and silane, germane, stannane are known, but plumbane, i.e., $P b H_{4}$ is very unstable. This is due to the mismatch of the size for big group $14$ elements and very small $H$ .

Suggest Corrections