Leela and madan collectea their CD's and sold them such that each C.D. was sold at the same amount as number of C.D's. From this amount colluted leela juist borrowed Rs.10, then madan borrowed RS.10, they borrowed money alternately until amount less than Rs.10 was left for Madan to borrow. Find has much was left for Madan to borrowed at the end

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Solution

Let total amount is $n^{2}$
Total borrowed amount $= (2 u + 1) 10$
$n^{2} - (2 u + 1) 10 < 10$
True for $n = 6 u = 1$
So, the left amount $= 6.$

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Let total amount is n2Total borrowed amount =(2u+1)10n2−(2u+1)10<10True for n=6u=1So, the left amount =6.

Let total amount is $n^{2}$
Total borrowed amount $= (2 u + 1) 10$
$n^{2} - (2 u + 1) 10 < 10$
True for $n = 6 u = 1$
So, the left amount $= 6.$