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Question

(1+cosπ10)(1+cos3π10)(1+cos7π10)(1+cos9π10)=116

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Solution

By supplementary rule,
cos (π - 4) = -cos A
L.H.S. = (1+cosπ10)(1+cos3π10)(1cos3π10)(1cosπ10)
= (1cos2π10)(1cos23π10)=sin218sin254
=(514.5+14)2=116

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