MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Constant

1 + xm 1 - xn...

Question

${(1 + x)}^{m} {(1 - x)}^{n}$ $x^{2}$ $- 6$ .
Find absolute value at $x = 0$

A

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

- 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $6$
At $x = 0$ ,
${(1 + x)}^{m} {(1 - x)}^{n} {(x)}^{2} - 6 = {(1 + 0)}^{m} {(1 - 0)}^{n} 0^{2} - 6 = - 6$
So, the absolute value of above expression is $| - 6 | = 6.$

Suggest Corrections

thumbs-up

0

Similar questions

Q. If the coefficients of

x

x^{2}

in the expansion of

{(1 + x)}^{m} {(1 - x)}^{n}

3

- 6

respectively. Find the values of

m

n

Q. If in the expansion of

(1 + x)^{m} \cdot (1 - x)^{n}

, the coefficients of

x

x^{2}

3

- 6

respectively, then

Q. If in the expansion of

{(1 + x)}^{m} {(1 - x)}^{n}

, the coefficient of

x

x^{2}

3

- 6

respectively, then

m

Q. Find the value of

(x^{2} + \frac{1}{x^{2}}) - 4 (x + \frac{1}{x}) + 6 = 0

Q. Find a positive value of

m

for which the coefficient of

x^{2}

in the expansion

{(1 + x)}^{m}

6

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Definition of Variables

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon