CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Composite Function

11 2 + 12 2 +...

Question

$(11^{2} + 12^{2} + 13^{2} + . . . . . 20^{2}) =$ ?

A

385

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

2485

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

2870

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

3255

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2485$
(112+122+132+.....202)=(12+22+32+.....202)−(12+22+32+.....102)[Ref:(12+22+32+.....n2)=16n(n+1)(2n+1)]

Suggest Corrections

thumbs-up

2

Similar questions

(11)^{2} + (12)^{2} + (13)^{2} + \dots + (20)^{2}

10^{2} + 11^{2} + 12^{2} + . . . . + 20^{2}

Q. Sum infinite terms of the series

{cot}^{- 1} (1^{2} + \frac{3}{4}) + {cot}^{- 1} (2^{2} + \frac{3}{4}) + {cot}^{- 1} (3^{2} + \frac{3}{4}) + \dots

Q. Sum to infinite terms of the series

c o t^{- 1} (1^{2} + \frac{3}{4}) + c o t^{- 1} (2^{2} + \frac{3}{4}) + c o t^{- 1} (3^{2} + \frac{3}{4}) + . . . . . . .

Q. The sum of the infinite terms of the series

{cot}^{- 1} (1^{2} + \frac{3}{4}) + {cot}^{- 1} (2^{2} + \frac{3}{4}) + {cot}^{- 1} (3^{2} + \frac{3}{4}) + \dots

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Composite Functions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Composite Function

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon