$(4 p x^{2} + 5 q^{2} y - 9 r z) - (- 3 q^{2} y + 7 p x^{2} - r z) =$

11 p x^{2} + 9 q^{2} y - 10 r z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3 p x^{2} + 8 q^{2} y - 8 r z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

11 p x^{2} + 8 q^{2} y - 8 r z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3 p x^{2} - 8 q^{2} y - 10 r z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $- 3 p x^{2} + 8 q^{2} y - 8 r z$
$(4 p x^{2} + 5 q^{2} y - 9 r z) - (- 3 q^{2} y + 7 p x^{2} - r z)$
$= 4 p x^{2} + 5 q^{2} y - 9 r z + 3 q^{2} y - 7 p x^{2} + r z$
$= 4 p x^{2} - 7 p x^{2} + 5 q^{2} y + 3 q^{2} y - 9 r z + r z$
$= - 3 p x^{2} + 8 q^{2} y - 8 r z$

Suggest Corrections

Similar questions

If α β, α a n d α + β are the zeroes of the polynomial, f (x) = x^{3} - 3 p x^{2} + q x - r, then which of the following relations is correct.

x^{3} + 3 p x^{2} + 3 q x + r = 0

f (x) = x^{3} - 3 p x^{2} + q x - r

x^{3} + 3 p x^{2} + 3 q x + r = 0

x^{3} + 3 p x^{2} + 3 q x + r = 0

Join BYJU'S Learning Program