${(7 {(64^{1 / 3} + 27^{1 / 3})}^{3})}^{1 / 4}$

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Solution

$[7 [(64)^{1 / 3} + (27)^{1 / 3}]^{3}]^{1 / 4} = [7 (4 + 3)^{3}]^{1 / 4} = [7^{4}]^{1 / 4} = 7$

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Similar questions

{⎡ ⎢ ⎣ 7 (64^{\frac{1}{3}} + 27^{\frac{1}{3}})^{3} ⎤ ⎥ ⎦}^{\frac{1}{4}}

{(5 {(8^{1 / 3} + 27^{1 / 3})}^{3})}^{1 / 4}

{5 (8^{\frac{1}{3}} + 27^{\frac{1}{3}})^{3}}^{\frac{1}{4}}

Write the value of ${5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}}^{\frac{1}{4}}$

{\{5 (8^{1 / 3} + 27^{1 / 3})^{3}\}}^{1 / 4} .

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