The correct option is C 74?+(81/7× 6 5/19 ) = 5^3 ⇒ ? + 57/7×119/19= 125 ⇒ ? +51 = 125 ⇒ ? = 125 51 = 74 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Quantitative Aptitude

Base Systems

?+8 1/7× 6 5/...

Question

$? + (8 \frac{1}{7} \times 6 \frac{5}{19}) = 5^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 74
$? + (8 \frac{1}{7} \times 6 \frac{5}{19}) = 5^{3} \Rightarrow ? + \frac{57}{7} \times \frac{119}{19} = 125 \Rightarrow ? + 51 = 125 \Rightarrow ? = 125 - 51 = 74$

Suggest Corrections

Similar questions

Q. Solve:

{(\frac{9}{25})}^{- 3 / 2} \times {(\frac{7}{5})}^{3} \times {(\frac{81}{49})}^{1 / 2}

Find the median of the following data set.

12 65 3 8 23 64 19 53 0 24 57 15 39

Find the product, using suitable properties:

(a) $26 \times (- 48) + (- 48) \times (- 36)$

(b) $8 \times 53 \times (- 125)$

(d) $(- 41) \times 102$

(e) $625 \times (- 35) + (- 625) \times 65$

(f) $7 \times (50 - 2)$

(g) $(- 17) \times (- 29)$

(h) $(- 57) \times (- 19) + 57$

Solve the equation 4 $x^{2}$ + 7x = 1 by the method of completing the square. In one of the options the positive root and the converted form of the equation after completing the square is given. Select this option.

Solve the equation 4 $x^{2}$ + 7x = 1 by the method of completing the square. In one of the options, one of the roots and the converted form of the equation, after completing the square is given. Select this option.

Join BYJU'S Learning Program

?+(817×6519)=53

The correct option is D 74?+(817×6519)=53⇒?+577×11919=125⇒?+51=125⇒?=125−51=74

$? + (8 \frac{1}{7} \times 6 \frac{5}{19}) = 5^{3}$

The correct option is D 74
$? + (8 \frac{1}{7} \times 6 \frac{5}{19}) = 5^{3} \Rightarrow ? + \frac{57}{7} \times \frac{119}{19} = 125 \Rightarrow ? + 51 = 125 \Rightarrow ? = 125 - 51 = 74$