$(a + 2 b + 3 c) - (4 a + 6 b - 5 c)$ is equivalent to:

- 4 a - 8 b - 2 c

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- 4 a - 4 b + 8 c

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- 3 a + 8 b - 2 c

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- 3 a - 4 b - 2 c

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- 3 a - 4 b + 8 c

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Solution

The correct option is E $- 3 a - 4 b + 8 c$
The value of $(a + 2 b + 3 c) - (4 a + 6 b - 5 c)$
$\Rightarrow a + 2 b + 3 c - 4 a - 6 b + 5 c$
$\Rightarrow - 3 a - 4 b + 8 c$

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∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 c \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

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