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Byju's Answer
Standard XII
Mathematics
Determinant
| 0 -a b ...
Question
∣
∣ ∣
∣
0
−
a
b
a
0
c
−
b
−
c
0
∣
∣ ∣
∣
=
0
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Solution
∣
∣ ∣
∣
1
a
−
b
−
a
0
−
c
b
c
0
∣
∣ ∣
∣
=
0
(
0
+
c
2
)
−
a
(
0
+
b
c
)
−
b
(
−
a
c
−
0
)
=
−
a
b
c
+
a
b
c
=
0
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0
Similar questions
Q.
If
C
0
1
+
C
1
2
+
C
2
3
=
0
,where
C
0
,
C
1
,
C
2
are all real, the equation
C
2
x
2
+
C
1
x
+
C
0
=
0
has:
Q.
If
∣
∣ ∣
∣
a
b
a
+
b
b
c
b
+
c
a
+
b
b
+
c
0
∣
∣ ∣
∣
=
0
;
then a, b, c are in
Q.
If
∣
∣ ∣
∣
a
b
a
+
b
b
c
b
+
c
a
+
b
b
+
c
0
∣
∣ ∣
∣
=
0
, then
a
,
b
,
c
are in
Q.
If
∣
∣ ∣
∣
a
b
a
α
+
b
b
c
b
α
+
c
a
α
+
b
b
α
+
c
0
∣
∣ ∣
∣
=
0
, then a, b, c are in
Q.
Prove that
△
=
∣
∣ ∣
∣
a
b
a
α
+
b
b
c
b
α
+
c
a
α
+
b
b
α
+
c
0
∣
∣ ∣
∣
=
0
if a,b,c are in G.P.
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