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Question

∣ ∣ ∣1aa21bb21cc2∣ ∣ ∣=(ab)(bc)(ca)

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Solution

R1R1R3
R2R2R3
∣ ∣ ∣0aca2c20bcb2c21cc2∣ ∣ ∣=(ab)(bc) ∣ ∣ ∣01a+c01b+c1c02∣ ∣ ∣
Expanding along C1, (ac)(bc)(b+cac)
=(ac)(bc)(ba)=(ab)(bc)(ca).

1208003_1392621_ans_c8d76f2c119d47be997c494399dcf0c7.jpg

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