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Question

∣ ∣ ∣a2+1abacabb2+1bccacbc2+1∣ ∣ ∣=1+a2+b2+c2

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Solution

∣ ∣ ∣a2+1abacabb2+1bccacbc2+1∣ ∣ ∣=(a2+1)((b2+1)(c2+1)b2c2)ab(abc2+ababc2)+ac(ab2cab2cac)
=(a2+1)(b2c2+b2+c2+1b2c2)ab(ab)+ac(ac)
=a2b2+a2c2+a2+b2+c2+1a2b2a2c2
=a2+b2+c2+1
= R.H.S

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