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Question

∣ ∣a+ba+2ba+3ba+2ba+3ba+4ba+4ba+5ba+6b∣ ∣=

A
a2+b2+c23abc
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B
3abc
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C
3a+5b
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D
0
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Solution

The correct option is D 0
∣ ∣a+ba+2ba+3ba+2ba+3ba+4ba+4ba+5ba+6b∣ ∣
=∣ ∣a+bbba+2bbba+4bbb∣ ∣ [C12C2C1C13C3C2]
=0 Ans [C2=C3]

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