Question

$(\frac{1}{125}\times 7^{-3})=\frac{1}{5^3}\times 7^{-3}$ in simplified form is $\frac{1}{{35}^m}$. The value of $m$ is

Answer 1

$(\frac{1}{125}\times 7^{-3})=\frac{1}{5^3}\times 7^{-3}$
$\Rightarrow 5^{-3}\times 7^{-3}$

$=(5\times 7{)}^{-3}$

$={35}^{-3}$

$=\frac{1}{{35}^3}$