- 1-cos - 12 -isin - 12 1-cos - 12 -isin - 12 - 72 -

The correct option is B 1 1+cos( π #160; 2 #160; ) #160; +isin( π #160; 2 #160; ) #160; #160; 1+cos( π #160; 2 #160; ) # ...

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Integration by Substitution

[ 1+cos π 12 ...

Question

${⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \frac{1 + cos (\frac{π}{12}) + i sin (\frac{π}{12})}{1 + cos (\frac{π}{12}) - i sin (\frac{π}{12})} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦}^{72} =$

0

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\frac{1}{2}

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Similar questions

(c o s \frac{π}{8} + i s i n \frac{π}{8}) \times (c o s \frac{π}{12} + i s i n \frac{π}{12}) \times (c o s \frac{π}{24} + i s i n \frac{π}{24}) \times (c o s \frac{π}{4} + i s i n \frac{π}{4})

{⎛ ⎜ ⎜ ⎝ \begin{matrix} \frac{1 + cos \frac{π}{8} - i sin \frac{π}{8}}{1 + cos \frac{π}{8} + i sin \frac{π}{8}} \end{matrix} ⎞ ⎟ ⎟ ⎠}^{8}

{(\frac{1 + c o s \frac{π}{2} - i s i n \frac{π}{2}}{1 + c o s \frac{π}{2} + i s i n \frac{π}{2}})}^{2}

{⎛ ⎜ ⎜ ⎝ \frac{1 + cos \frac{π}{8} - i sin \frac{π}{8}}{1 + cos \frac{π}{8} + i sin \frac{π}{8}} ⎞ ⎟ ⎟ ⎠}^{8} =

{(\frac{1 + c o s \frac{π}{8} - i s i n \frac{π}{8}}{1 + c o s \frac{π}{8} + i s i n \frac{π}{8}})}^{8}

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