${({C H}_{3})}_{2} C H C l + N a I ⟶ {({C H}_{3})}_{2} C H I + N a C l$
The above reaction is known as:

Perkin's rection

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Finkelstein's reaction

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Fitting reaction

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Sabatier and Senderan's reaction

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Solution

The correct option is B Finkelstein's reaction
Finkelstein reaction:
$R C l$ or $R - B r N a I - - \to R - I$

Suggest Corrections

Similar questions

R - C l + N a I a c e t o n e - --- \to R - I + N a C l

R C l + N a I Dry acetone ⟶ R - I + N a C l

R C l + N a I Dry acetone - ------ \to R - I + N a C l ↓

C H_{3} C H_{2} C l + N a I A c e t o n e - ---- \to C H_{3} C H_{2} I + N a C l

{C H}_{3} C \equiv \oplus C N a + {({C H}_{3})}_{2} C H C l ⟶

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