${({C H}_{3})}_{3} C - M g C l$ on reaction with $D_{2} O$ produces :

{({C H}_{3})}_{3} C D

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{({C H}_{3})}_{3} O D

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({C D}_{3}) C M g C l

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{({C D}_{3})}_{3} O D

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Solution

The correct option is A ${({C H}_{3})}_{3} C D$
${({C H}_{3})}_{3} C - M g C l$ is a strong base.

${({C H}_{3})}_{3} C - M g C l$ + $D_{2} O$ $⟶$ ${({C H}_{3})}_{3} C - D$ + $M g B r O D$ .

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