cos- -cos- 2 - sin- -sin- 2 -4sin 2 - - -2

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Trigonometric Ratios of Compound Angles

cosα -cosβ 2...

Question

${(cos α - cos β)}^{2} + {(sin α - sin β)}^{2} = 4 {sin}^{2} {(α - β) / 2}$

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{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = 4 {cos}^{2} {(α - β) / 2}

{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = λ {cos}^{2} \frac{(α - β)}{2}

λ

{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = b {cos}^{2} (\frac{α - β}{2})

(cos α + cos β)^{2} + (sin α + sin β)^{2} =

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{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = . . . . . . . . .

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