Question

${\left(Coulomb\right)}^2{J}^{-1}$ can be the unit of :

• A. electric resistence
• B. electric energy
• C. electric capacity
• D. electric power

Answer 1

Answer: (C)

electric capacity

Electric energy $=M{L}^2{T}^{-2}$
Electric power $=M{L}^2{T}^{-3}$
Electric resistance $=M{L}^2{I}^{-2}{T}^{-3}$
Electric capacity $=M^{-1}{L}^{-2}{I}^2{T}^4$$=\left(\frac{I^2{T}^2}{\left(M^1{L}^2{T}^{-2}\right)}\right)=\left(\frac{Q^2}{J}\right)$
Hence, option C is correct.