1-sin-1-cos-1-1-cosec-tan-

(1+sinα/1+ cos α)(1+ sec α/1+ cosec α) ⇒(1+ sin α )/(1+ cosα )(1+1/cosα )/(1+1/sin α ) ⇒(1+ sin α )/(1+ cos α ).(cos α +1)/(sin α +1).sinα/cos α= ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of n Terms

1+sinα1+cosα1...

Question

$(\frac{1 + sin α}{1 + cos α}) (\frac{1 + sec α}{1 + c o s e c α}) = tan α$ .

Open in App

Solution

Suggest Corrections

Similar questions

\frac{1 + sin α}{1 + cos α} . \frac{1 + sec α}{1 + cosec α} = tan α .

sin α = \frac{5}{13}

\frac{π}{2} < α < π

\frac{sec α + tan α}{c o s e c α - cot α}

0 < α < π / 2

sin α + cos α + tan α + cot α + sec α + c o s e c α = 7

sin 2 α

x^{2} - 44 x - 36 = 0

[sin α + sin (180^{\circ} - α) + sin (180^{\circ} + α)] c o s e c α =

(s i n α + c o s α) (t a n α + c o t α) = s e c α + c o s e c α

Join BYJU'S Learning Program