CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Standard Values of Trigonometric Ratios

1+tan2A1+2A =...

Question

$(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {tan}^{2} A$

Open in App

Solution

LHS $= \frac{1 + t a n^{2} A}{1 + c o t^{2} A} = \frac{s e c^{2} A}{c o s e c^{2} A} = \frac{s i n^{2} A}{c o s^{2} A} = t a n^{2} A = R H S$

Suggest Corrections

thumbs-up

3

Similar questions

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - {tan}^{2} A}{1 - {cot}^{2} A})}^{2} = {tan}^{2} A

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - {tan}^{2} A}{1 - {cot}^{2} A})}^{2} = {tan}^{2} A

Q. tan²A/1+tan²A + cot²A/1+cot²A=sec²Acos²A-2secAcosA

\frac{{tan}^{2} A}{1 + {tan}^{2} A} + \frac{{cot}^{2} A}{1 + {cot}^{2} A} = 1

\frac{1 - {tan}^{2} A}{{cot}^{2} A - 1} = {tan}^{2} A

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trigonometric Ratios of Specific Angles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard Values of Trigonometric Ratios

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon