Question

$(\frac{4}{6}\times \frac{5}{8})÷(\frac{1}{3}\times \frac{2}{4})+(\frac{-1}{3}-\frac{1}{4})$ is $\frac{a}{12}$. Find $a$

Answer 1

$(\frac{4}{6}\times \frac{5}{8})÷(\frac{1}{3}\times \frac{2}{4})+(\frac{-1}{3}-\frac{1}{4})$

$=(\frac{4}{6}\times \frac{5}{8})\times (\frac{3}{1}\times \frac{4}{2})+(\frac{-1}{3}-\frac{1}{4})$

$=(\frac{4}{6}\times \frac{5}{8})\times (\frac{3}{1}\times \frac{4}{2})+\left(\frac{-7}{12}\right)$

$=\left(\frac{5}{2}\right)+\left(\frac{-7}{12}\right)$

$=\frac{23}{12}$

hence, required value of $a=23$