d 2 y d x 2 2 -cos dy dx -0

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Order of a Differential Equation

d 2 y d x 2 ...

Question

${(\frac{d^{2} y}{d x^{2}})}^{2} + cos (\frac{d y}{d x}) = 0$

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(\frac{d^{2} y}{d x^{2}})^{2} + cos (\frac{d y}{d x}) = 0

Determine order and degree(if defined) of differential equation

Determine order and degree (when defined) of differential equations.
${(\frac{d^{2} y}{d x^{2}})}^{2} + c o s (\frac{d y}{d x}) = 0.$

\frac{d^{4} y}{d x^{4}} + sin (y^{'''}) = 0

y^{'} + 5 y = 0

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{(\frac{d^{2} y}{d x^{2}})}^{2} - cos (\frac{d y}{d x}) = 0

\frac{d^{2} y}{d x^{2}} = cos 3 x + sin 3 x

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y + 2 y^{''} + y = 0

y^{'} + y = e^{x}

y^{''} + (y) 2 + 2 y = 0

y^{''} + 2 y + sin y = 0

1 + {(\frac{d^{2} y}{d x^{2}})}^{2} = {[2 + (\frac{d y}{d x})]}^{3 / 2}

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