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Question

(d3ydx3)2/3+43d2ydx2+5dydx=0

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Solution

Given,

(d3ydx3)23+43d2ydx2+5dydx=0

(d3ydx3)23=3d2ydx25dydx4

cubing on both sides, we get,

(d3ydx3)2=(3d2ydx25dydx4)3

Order=3

Degree=2

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