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Question

(xaxb)a2ab+b2×(xbxc)b2bc+c2×(xcxa)c2ac+a2

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Solution

(xaxb)a2ab+b2×(xbxc)b2bc+c2×(xcxa)c2ac+a2

On further simplification, we have:

x(a+b)(a2ab+b2)×x(b+c)(b2bc+c2)×x(c+a)(c2ca+a2)
[1ax=ax]

=xa3+b3.xb3+c3.xc3+a3
[(x+y)(x2xy+y2)=x3+y3]

=xa3+b3+b3+c3+a3
=x2(a3+b3+c3)

Hence, simplified value is x2(a3+b3+c3)

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