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Question

(xmxn)m+n×(xnxl)n+l×(xlxm)l+m.

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Solution

(xmxn)m+n×(xnxl)n+l×(xlxm)l+m
[xmxn=xmn]
[(x)mn]m+n×[(x)nl]n+l×[(x)lm]l+m
[xm×xn=xm+n] & [(a+b)(ab)=a2+b2]
xm2n2×xn2l2×xl2m2
xm2n2+n2l2+l2m2
xo=1.

1178010_1300443_ans_409f19b2d34d4cadbb39565b64151838.jpg

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