${[F e F_{6}]}^{4 -}$ is paramagnetic because:

F^{-}

is a weaker ligand

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F^{-}

is a stronger ligand

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F^{-}

is a flexidinate ligand

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F^{-}

us a chelating ligand

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Solution

The correct option is D $F^{-}$ is a weaker ligand
${[F e F_{6}]}^{4 -}$ is paramagnetic because $F^{-}$ is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. $F e^{2 +}$ has $3 d^{6}$ electronic configuration.

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[FeF6]4− is paramagnetic because:

The correct option is D F− is a weaker ligand[FeF6]4− is paramagnetic because F− is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. Fe2+ has 3d6 electronic configuration.

${[F e F_{6}]}^{4 -}$ is paramagnetic because:

The correct option is D $F^{-}$ is a weaker ligand
${[F e F_{6}]}^{4 -}$ is paramagnetic because $F^{-}$ is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. $F e^{2 +}$ has $3 d^{6}$ electronic configuration.