1-10-1-102-1-103-1-104- -

The correct option is C 0.1111 ( 1/10 ) + ( 1/10 )^2 + ( 1/10 )^3 + ( 1/10 )^4= 0.1111 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Sum of Infinite Terms of a GP

1/10+1/102+1/...

Question

$(\frac{1}{10}) + {(\frac{1}{10})}^{2} + {(\frac{1}{10})}^{3} + {(\frac{1}{10})}^{4} =$ ?

1.1111

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0111

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0101

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1111

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.1110

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D
0.1111

$(\frac{1}{10}) + {(\frac{1}{10})}^{2} + {(\frac{1}{10})}^{3} + {(\frac{1}{10})}^{4} = 0.1111$

Suggest Corrections

Similar questions

Find the value of

$(2 \times 10^{4}) + (3 \times 10^{3}) + (1 \times 10^{2}) + (6 \times 10^{1}) + (7 \times 10^{0}) + (4 \times 10^{- 1}) + (2 \times 10^{- 2}) + (8 \times 10^{- 3})$

Q. If

a = 111.........1      55, b = 1 + 10 + 10^{2} + 10^{3} + 10^{4}

and

c = 1 + 10^{5} + 10^{10} + . . . . + 10^{50}

, then show following.
(i) 'a' is a not composite number
(ii)

a i s n o t e q u a l b c

(1 \times 10^{3}) + (2 \times 10^{2}) + (3 \times 10^{0}) + (1 \times 10^{- 1}) + (2 \times 10^{- 2})

Q. Solve

10^{- 1} \times 10^{2} \times 10^{- 3} \times 10^{4} \times 10^{5} \times 10^{6}

Q. Simplify:

10^{- 1} \times 10^{2} \times 10^{- 3} \times 10^{4} \times 10^{- 5} \times 10^{6}

Join BYJU'S Learning Program

(110)+(110)2+(110)3+(110)4= ?

The correct option is D 0.1111 (110)+(110)2+(110)3+(110)4=0.1111

$(\frac{1}{10}) + {(\frac{1}{10})}^{2} + {(\frac{1}{10})}^{3} + {(\frac{1}{10})}^{4} =$ ?

The correct option is D
0.1111

$(\frac{1}{10}) + {(\frac{1}{10})}^{2} + {(\frac{1}{10})}^{3} + {(\frac{1}{10})}^{4} = 0.1111$