${(- \frac{1}{2})}^{3} \times 3^{2} \times {(\frac{3}{4})}^{2}$

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Solution

$(\frac{- 1}{2})^{3} \times 3^{2} \times (\frac{3}{4})^{2} = (\frac{- 1}{2^{3}}) \times 9 \times (\frac{9}{16}) = (\frac{- 81}{8 \times 16}) = (\frac{- 81}{128})$

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