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Question

 (1+cosϕ+isinϕ1+cosϕisinϕ)n =



Your Answer
A

Correct Answer
B

Your Answer
C

Your Answer
D


Solution

The correct option is B


  [2cos2(ϕ2)+2isin(ϕ2)cos(ϕ2)2cos2(ϕ2)2isin(ϕ2)cos(ϕ2)]n

=  [2cos(ϕ2)+2isin(ϕ2)2cos(ϕ2)2isin(ϕ2)]n = [ei(ϕ2)ei(ϕ2)]=   (eiϕ)n       

=cosnϕ + isinnϕ.

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