Question 562-53-5-23-1

Name: EXEMP - Grade 07 - Mathematics - Exponents & Powers - Q56
Uploaded: 2022-07-04T10:36:42+05:30
Description: False Here, ( 2/5 )^3÷ ( 5/2 )^3= ( 2/5 )^3× ( 2/5 )^3 = ( 2/5 )^3+3= ( 2/5 )^6 Hence, ( 2/5 )^3÷ ( 5/2 )^3≠ 1 ...

False Here, ( 2/5 )^3÷ ( 5/2 )^3= ( 2/5 )^3× ( 2/5 )^3 = ( 2/5 )^3+3= ( 2/5 )^6 Hence, ( 2/5 )^3÷ ( 5/2 )^3≠ 1 ...

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Standard VII

Mathematics

Exponents with Like Bases

Question 562/...

Question

Question 56

${(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} = 1$

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Solution

False
Here, ${(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} = {(\frac{2}{5})}^{3} \times {(\frac{2}{5})}^{3} = {(\frac{2}{5})}^{3 + 3} = {(\frac{2}{5})}^{6} H e n c e, {(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} \neq 1$

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Similar questions

Q. A fraction equivalent to

\frac{2}{3}

is

(a)

\frac{2 + 3}{3 + 3}

(b)

\frac{2 - 1}{3 - 1}

(c)

\frac{2 \times 5}{3 \times 5}

(d)

\frac{2 + 5}{3 + 5}

Q. The sum of the series

\frac{30}{(6 - 5) (6^{2} - 5^{2})} + \frac{30^{2}}{(6^{2} - 5^{2}) (6^{3} - 5^{3})} + \frac{30^{3}}{(6^{3} - 5^{3}) (6^{4} - 5^{4})} + \dots \infty

{(\frac{2}{3})}^{- 5}

is equal to
(a)

{(\frac{- 2}{3})}^{5}

(b)

{(\frac{3}{2})}^{5}

(c)

\frac{2 x - 5}{3}

(d)

\frac{2}{3 \times 5}

Q. Simplify:

{[\frac{2^{2}}{15}]}^{4} \times {[\frac{5^{3}}{2^{3}}]}^{3} + {(\frac{5}{9})}^{3}

Q. If a =

2^{3} \times 3^{3} \times 7^{2}

and

b = 2^{2} \times 3^{2} \times 5^{3},

which is true?

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Exponents with Like Bases

Standard VII Mathematics

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Question 56 (25)3÷(52)3=1

False Here, (25)3÷(52)3=(25)3×(25)3=(25)3+3=(25)6Hence, (25)3÷(52)3≠1

Question 56

${(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} = 1$

False
Here, ${(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} = {(\frac{2}{5})}^{3} \times {(\frac{2}{5})}^{3} = {(\frac{2}{5})}^{3 + 3} = {(\frac{2}{5})}^{6} H e n c e, {(\frac{2}{5})}^{3} \div {(\frac{5}{2})}^{3} \neq 1$