3-4a2 - 3b2 and 4a2 - 5-3b2

( 3 4a^2 + 3b^2) + ( #10;4a^2 5 3b^2) #10; #10; ( 3 4a^2 + 4a^2) + ( #10;3b^2 5 3b^2) #10; #10; 3a^2 + 16a^2 4 + 9b^2 5b^2 ...

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Byju's Answer

Standard IX

Mathematics

Rationalisation

3/4a2 + 3b2 a...

Question

$(\frac{3}{4} a^{2} + 3 b^{2}) a n d (4 a^{2} - \frac{5}{3} b^{2})$

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Solution

$(\frac{3}{4} a^{2} + 3 b^{2}) + (4 a^{2} - \frac{5}{3} b^{2})$

$(\frac{3}{4} a^{2} + 4 a^{2}) + (3 b^{2} - \frac{5}{3} b^{2})$

$\frac{3 a^{2} + 16 a^{2}}{4} + \frac{9 b^{2} - 5 b^{2}}{3}$

$\frac{19 a^{2}}{4} + \frac{4 b^{2}}{3}$

$\frac{57 a^{2} + 16 b^{2}}{12}$

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Similar questions

Q. If

a : b = 2 : 3

and

b : c = 4 : 5

, find

a^{2} : b^{2} : b c

Q. If

a = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}

and

b = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}

Find

a^{2} + b^{2} - 6 a b

If $a = \frac{\sqrt{5} + 1}{\sqrt{5} - 1} a n d b = \frac{\sqrt{5} - 1}{\sqrt{5} + 1}, t h e v a l u e o f (\frac{a^{2} + a b + b^{2}}{a^{2} - a b + b^{2}})$ is :

Q. If

a : b = 2 : 3

and

b : c = 4 : 5

is then

a^{2} : b^{2} : b c

Q. ADD :

(\frac{3}{2} a^{2} + 3 b^{2})

and

(4 a^{2} - \frac{5}{3} b^{2})

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(34a2+3b2)and(4a2−53b2)

(34a2+3b2)+(4a2−53b2) (34a2+4a2)+(3b2−53b2) 3a2+16a24+9b2−5b23 19a24+4b23 57a2+16b212

$(\frac{3}{4} a^{2} + 3 b^{2}) a n d (4 a^{2} - \frac{5}{3} b^{2})$

$(\frac{3}{4} a^{2} + 3 b^{2}) + (4 a^{2} - \frac{5}{3} b^{2})$

$(\frac{3}{4} a^{2} + 4 a^{2}) + (3 b^{2} - \frac{5}{3} b^{2})$

$\frac{3 a^{2} + 16 a^{2}}{4} + \frac{9 b^{2} - 5 b^{2}}{3}$

$\frac{19 a^{2}}{4} + \frac{4 b^{2}}{3}$

$\frac{57 a^{2} + 16 b^{2}}{12}$