Question

$\left[\frac{3\sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4\sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{\sqrt{8}-\sqrt{12}}\right]=?$

• A.
• B.
• C. 1
• D. 0

Answer 1

Answer: (B)

Upon rationalizing the denominator, we get

$\frac{3\sqrt{2}(\sqrt{6}-\sqrt{3})}{3}-\frac{4\sqrt{3}(\sqrt{6}-\sqrt{2})}{4}+3(\sqrt{2}-\sqrt{3})$

= 5$\sqrt{3}$