Question

Question 57

${\left(\frac{4}{3}\right)}^5\times {\left(\frac{5}{7}\right)}^5={(\frac{4}{3}+\frac{5}{7})}^5$

Answer 1

False
Here, ${\left(\frac{4}{3}\right)}^5\times {\left(\frac{5}{7}\right)}^5={(\frac{4}{3}\times \frac{5}{7})}^5(\because a^n.b^n=(a.b{)}^n)and{\left[(\frac{4}{3}+\left(\frac{5}{7}\right))\right]}^5=(\frac{4}{3}+\frac{7}{5}){(\frac{4}{3}+\frac{7}{5})}^{4}Hence,{\left(\frac{4}{3}\right)}^5\times {\left(\frac{5}{7}\right)}^5\ne {(\frac{4}{3}+\frac{7}{5})}^5$