The correct option is C 0 We have to use the BODMAS rule for the calculations. So, ( 5/3+17/51 )÷2 5+4 = ( 5/3+1/3 )÷2 5+4 =(2)÷2 5+4 =1 5+4 = 1+4 5 =5 5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

BODMAS

5/3+17/51 ÷ 2...

Question

$(\frac{5}{3} + \frac{17}{51}) \div 2 - 5 + 4 =$

-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
0

$We have to use the BODMAS rule for the calculations. So, (\frac{5}{3} + \frac{17}{51}) \div 2 - 5 + 4 = (\frac{5}{3} + \frac{1}{3}) \div 2 - 5 + 4 = (2) \div 2 - 5 + 4 = 1 - 5 + 4 = 1 + 4 - 5 = 5 - 5 = 0$

Suggest Corrections

Similar questions

Find the odd-one-out from the alternatives.

(1)

25, 5, 5

(2)

51, 3, 17

(3)

96, 6, 16

(4)

75, 5, 25

Q. Find

x

, if

5 \frac{1}{6} - [1 \frac{1}{5} + {2 \frac{3}{4} \div 5 \frac{1}{2} \div x - (\frac{5}{6} - \frac{2}{3})}] = 2 \frac{61}{120}

Multiply the following fractions:

(i) (ii) (iii)

(iv) (v) (vi)

(vii)

$20 + \frac{2}{5} + \frac{1}{4} + \frac{2}{3} + \frac{1}{2} = ?$

Q. If

5 \frac{1}{6} - [1 \frac{1}{5} + {2 \frac{3}{4} \div 5 \frac{1}{2} \div χ - (\frac{5}{6} - \frac{2}{3})}] = 2 \frac{61}{120}

then the value of x is

Join BYJU'S Learning Program

(53+1751)÷2−5+4=

The correct option is C 0 We have to use the BODMAS rule for the calculations. So,(53+1751)÷2−5+4=(53+13)÷2−5+4=(2)÷2−5+4=1−5+4=1+4−5=5−5=0

$(\frac{5}{3} + \frac{17}{51}) \div 2 - 5 + 4 =$

The correct option is C
0

$We have to use the BODMAS rule for the calculations. So, (\frac{5}{3} + \frac{17}{51}) \div 2 - 5 + 4 = (\frac{5}{3} + \frac{1}{3}) \div 2 - 5 + 4 = (2) \div 2 - 5 + 4 = 1 - 5 + 4 = 1 + 4 - 5 = 5 - 5 = 0$