Question

$(\frac{7}{-26}+\frac{16}{39})=?$

(a) $\frac{11}{78}$

(b) $\frac{-11}{78}$

(c) $\frac{11}{39}$

(d) $\frac{-11}{39}$

Answer 1

$\frac{7}{-26}+\frac{16}{39}=\frac{-21+32}{78}=\frac{11}{78}$