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Byju's Answer
Standard XI
Mathematics
Sum of Trigonometric Ratios in Terms of Their Product
cos A +cos B ...
Question
(
c
o
s
A
+
c
o
s
B
s
i
n
A
−
s
i
n
B
)
n
+
(
s
i
n
A
+
s
i
n
B
c
o
s
A
−
c
o
s
B
)
n
(n even or odd)=
A
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B
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C
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D
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Solution
The correct options are
B
C
The expression reduces to
c
o
t
n
A
−
B
2
+
c
o
t
n
B
−
A
2
If n is even, answer is (b) and if n is odd answer is (c).
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0
Similar questions
Q.
Assertion :
(
cos
A
+
cos
B
sin
A
−
sin
B
)
n
+
(
sin
A
+
sin
B
cos
A
−
cos
B
)
n
=
2
cot
n
(
A
−
B
2
)
if
n
is even
=
0
if
n
is odd. Reason:
cos
A
+
cos
B
sin
A
−
sin
B
=
cot
A
−
B
2
.
Q.
(
cos
A
+
cos
B
sin
A
−
sin
B
)
n
+
(
sin
A
+
sin
B
cos
A
−
cos
B
)
n
=
x
cot
n
A
−
B
2
or a, accordingly as n is even or odd. Find
x
+
a
Q.
(
cos
A
+
cos
B
sin
A
−
sin
B
)
n
+
(
sin
A
+
sin
B
cos
A
−
cos
B
)
n
=
2
cot
n
(
A
−
B
2
)
or
0
according as
n
is even or odd positive integer.
Q.
If
n
is an odd integer then
(
cos
A
+
cos
B
sin
A
−
sin
B
)
n
+
(
sin
A
+
sin
B
cos
A
−
cos
B
)
n
=
Q.
Find the value of
(
cos
A
+
cos
B
sin
A
−
sin
B
)
n
+
(
sin
A
+
sin
B
cos
A
−
cos
B
)
n
(where
n
is an even)
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Sum of Trigonometric Ratios in Terms of Their Product
Standard XI Mathematics
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