(pq)(a)×(qr)(b)×(rp)(c)=1. What is the relationship between a,b,c ?
a=b=c
abc=0
a+b+c = 0
abc = 1/2
None of these
(pq)a×(qr)b×(rp)c=po×qo×ro pa−c×qb−a×rc−b=po×qo×ro
So,a−c=0 b−a=0 c−b=0 Hence,a=b=c
If p + q + r = a + b + c = 0, then the determinant Δ=∣∣ ∣∣paqbrcqcrapbrbpcqa∣∣ ∣∣ equals