Question

$\{\frac{(si{n}^2{22}^o+si{n}^2{68}^o)}{(co{s}^2{22}^o+co{s}^2{68}^o)}+si{n}^2{63}^o+cos{63}^{o}sin{27}^o\}$ = ?

(a) 0 (b) 1 (c) 2 (d) 3

Answer 1

$\frac{si{n}^2{22}^o+si{n}^2{68}^o}{co{s}^2{22}^o+co{s}^2{68}^o}+si{n}^2{63}^o+sin{27}^o\times cos{63}^o$
$\frac{si{n}^2{22}^o+co{s}^2{22}^o}{si{n}^2{68}^o+co{s}^2{68}^o}+si{n}^2{63}^o+si{n}^2{27}^o$ [$\because sinA=cos(90-A),cosA=sin(90-A)$]

=$\frac{1}{1}+1$ [$\because si{n}^{2}A+co{s}^{2}A=1$]

= 1+1

= 2