X2 y-1-xy y-32-x-2 y1-xx-3 y21 is equal to-

The correct option is D y^5/x^3(x^2 y^ 1/x^3y^ 3 )^2÷(x^ 2y^1/x^ 3y^2 )^1 (x^2 y^ 1/x^3y^ 3 )^2×(x^ 3y^2/x^ 2y^1 )^1 (y^2/x )^2 ×(y/x ) (y^4/x^2×y/x=y^5/x^3 ) ...

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Byju's Answer

Standard VI

Mathematics

Set Builder Form

x2 y-1/xy y-3...

Question

${(\frac{x^{2} y^{- 1}}{x^{3} y^{- 3}})}^{2} \div {(\frac{x^{- 2} y^{1}}{x^{- 3} y^{2}})}^{1}$ is equal to-

x^{3} y^{5}

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\frac{x^{3}}{y^{5}}

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\frac{x^{- 3}}{y^{- 5}}

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\frac{y^{5}}{x^{3}}

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Solution

The correct option is D $\frac{y^{5}}{x^{3}}$
${(\frac{x^{2} y^{- 1}}{x^{3} y^{- 3}})}^{2} \div {(\frac{x^{- 2} y^{1}}{x^{- 3} y^{2}})}^{1}$
${(\frac{x^{2} y^{- 1}}{x^{3} y^{- 3}})}^{2} \times {(\frac{x^{- 3} y^{2}}{x^{- 2} y^{1}})}^{1}$
${(\frac{y^{2}}{x})}^{2} \times (\frac{y}{x})$
$(\frac{y^{4}}{x^{2}} \times \frac{y}{x} = \frac{y^{5}}{x^{3}})$

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The correct option is D y5x3(x2y−1x3y−3)2÷(x−2y1x−3y2)1 (x2y−1x3y−3)2×(x−3y2x−2y1)1 (y2x)2×(yx) (y4x2×yx=y5x3)

${(\frac{x^{2} y^{- 1}}{x^{3} y^{- 3}})}^{2} \div {(\frac{x^{- 2} y^{1}}{x^{- 3} y^{2}})}^{1}$ is equal to-