wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(xbxc)(b+c).(xaxb)(a+b).(xcxa)(a+c)=?


A

xabc

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

xa+b+c

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
E

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

1


(xbc)(b+c).(xab)(a+b).(xca)a+c=x(b2c2).x(a2b2).x(c2a2)=xb2c2+a2b2+c2a2=x0=1.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon