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Question

[^i,a,b]^i+[^j,a,b,]^j+[^k,a,b]^k=

A
a+b
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B
ab
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C
a×b
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D
b×a
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Solution

The correct option is C a×b
For any vector a=a1^i+a2^j+a3^k
=(a.^i)^i+(a.^j)^j+(a.^k)^k
[^i,a,b]^i=[^i(a×b)]^i
=[(a×b).^i]^i
=a×b

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