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Question

(IE)1 of Be is greater than that of B but (IE)2 of (B) is greater than that of Be.If true enter 1, else 0.

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Solution

Unpaired electron in B is easier to remove than that paired electron in Be. Hence (IE)1 of be > (IE)1 of B, and by (IE)1 Be+ and B+ are formed.
Now reserved is the case; removal of unpaired electron from Be+ is easier than that of paired electron from B+. Hence (IE)2 of B > (IE)2 of Be.

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