Question

$\left(K_{sp}\right)$ AgCl is $2.8\times {10}^{-10}$ at ${25}^{\circ }$ C. Calculate solubility of AgCl in $0.1\left(M\right)AgN{O}_3$

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

$AgCl\left(s\right)\rightleftharpoons A{g}^{+}\left(aq\right)+C{l}^{-}\left(aq\right)$
s s
$AgN{O}_3\to A{g}^{+}\left(aq\right)+N{O}_3^{-}\left(aq\right)$
0.1 0.1
$K_{sp}=\left[A{g}^{+}\right]\left[C{l}^{-}\right]=(0.1+S)\times S$
$AsS<<0.1K_{sp}\cong 0.1S$
$\therefore S=\frac{2.8\times {10}^{-10}}{{10}^{-1}}moleLi{t}^{-1}=2.8\times {10}^{-9}moleLi{t}^{-1}$