$[L^{1} M^{1} T^{- 2}]$ are the dimensions of ____

force

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impulse

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power

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kinetic energy

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Solution

The correct option is A force
$F o r c e = M a s s \times A c c e l e r a t i o n$

But, $A c c e l e r a t i o n = V e l o c i t y \times T i m e = [L T^{- 1}] [T^{- 1}] = [L T^{- 2}]$

Then, $F o r c e = [M] [L T^{- 2}] = [M^{1} L^{1} T^{- 2}]$

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[L1M1T−2] are the dimensions of ____

The correct option is A forceForce=Mass×AccelerationBut, Acceleration=Velocity×Time=[LT−1][T−1]=[LT−2]Then, Force=[M][LT−2]=[M1L1T−2]

$[L^{1} M^{1} T^{- 2}]$ are the dimensions of ____

The correct option is A force
$F o r c e = M a s s \times A c c e l e r a t i o n$

But, $A c c e l e r a t i o n = V e l o c i t y \times T i m e = [L T^{- 1}] [T^{- 1}] = [L T^{- 2}]$

Then, $F o r c e = [M] [L T^{- 2}] = [M^{1} L^{1} T^{- 2}]$