$∣ ∣ (a b + c a^{2}) (b c + a b^{2}) (c a + b c^{2}) ∣ ∣$

(a - b) (b - c) (c - a)

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- (a - b) (b - c) (c - a) (a + b + c)

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a b c (a - b) (b - c) (c - a)

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2 (a - b) (b - c) (c - a)

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Solution

The correct option is A $(a - b) (b - c) (c - a)$
We have,
$∣ ∣ (a b + c a^{2}) (b c + a b^{2}) (c a + b c^{2}) ∣ ∣$ $\Rightarrow a b c | (b + c a) (c + a b) (a + b c) |$
Hence this is the answer.

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