The correct option is D 0[ ( 4/3 )^ 2 ( 3/4 )^2]^2 = [ 1/ (4/3 )^2 nbsp; ( 3/4 )^2]^2 ∵ a^ m=1/a^m = [ ( 3/4 )^2 ( 3/4 )^2]^2 = 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Positive and Negative Powers

[4/3-2-3/42]2...

Question

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = ?$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1024}{81}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{81}{1024}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.0
${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = {⎡ ⎣ \frac{1}{{(\frac{4}{3})}^{2}} - {(\frac{3}{4})}^{2} ⎤ ⎦}^{2} ∵ a^{- m} = \frac{1}{a^{m}}$
$= {[{(\frac{3}{4})}^{2} - {(\frac{3}{4})}^{2}]}^{2}$
$= 0$

Suggest Corrections

Similar questions

Question 180(ii)

Simplify

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{- 2}$

Question 180(ii)

Simplify

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{- 2}$

\frac{- 3}{4} (\frac{2}{3} + \frac{- 5}{6}) = (\frac{- 3}{4} \times \frac{- 2}{3}) + (\frac{- 3}{4} \times \frac{- 5}{6})

{(\frac{1}{3})}^{3} \times {(\frac{- 3}{4})}^{2} \times (\frac{- 4}{3}) \times (\frac{3}{2})

\int {\sqrt{2 x^{2} - 3 x + 1}}_{d x}

Join BYJU'S Learning Program