- - 4-3 -2 - - 3-4 -2 -2 - nbsp-11024-8181-10240

The correct option is D 0[ ( 4/3 )^ 2 ( 3/4 )^2]^2 = [ 1/ (4/3 )^2 nbsp; ( 3/4 )^2]^2 ∵ a^ m=1/a^m = [ ( 3/4 )^2 ( 3/4 )^2]^2 = 0 ...

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Byju's Answer

Standard VIII

Mathematics

Negative Exponents

[ ( 4/3 )^-2...

Question

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = ?$

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\frac{1024}{81}

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\frac{81}{1024}

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0.0

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Solution

The correct option is D 0.0
${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = {⎡ ⎣ \frac{1}{{(\frac{4}{3})}^{2}} - {(\frac{3}{4})}^{2} ⎤ ⎦}^{2} ∵ a^{- m} = \frac{1}{a^{m}}$
$= {[{(\frac{3}{4})}^{2} - {(\frac{3}{4})}^{2}]}^{2}$
$= 0$

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Similar questions

Simplify :

$(i) 8^{\frac{4}{3}} + 25^{\frac{3}{2}} - {(\frac{1}{27})}^{- \frac{2}{3}} (i i) [(64)^{- 2}]^{- 3} \div [{(- 8)^{2}}^{3}]^{2} (i i i) (2^{- 3} - 2^{- 4}) (2^{- 3} + 2^{- 4})$

Simplify:

$(i) {{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}} \div {(\frac{1}{4})}^{- 3} (i i) (3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3} (i i i) {(\frac{1}{2}) \times (- 4)^{- 1}}^{- 1} (i v) {[{{(\frac{- 1}{4})}^{2}}^{- 2}]}^{- 1} (v) {{(\frac{2}{3})}^{2}}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}$

Evaluate :
$(i) \frac{2}{3} - \frac{4}{5} (i i) \frac{- 4}{9} - \frac{2}{- 3} (i i i) - 1 - \frac{4}{9} (i v) \frac{- 2}{7} - \frac{3}{- 14} (v) \frac{- 5}{18} - \frac{- 2}{9} (v i) \frac{5}{21} - \frac{- 13}{42}$

{[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = ?

Q. Simplify:

(i i i)

(2^{- 3} - 2^{- 4}) (2^{- 3} + 2^{- 4})

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[(43)−2−(34)2]2= ?

The correct option is D 0.0[(43)−2−(34)2]2=⎡⎣1(43)2−(34)2⎤⎦2 ∵a−m=1am =[(34)2−(34)2]2 = 0

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = ?$

The correct option is D 0.0
${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{2} = {⎡ ⎣ \frac{1}{{(\frac{4}{3})}^{2}} - {(\frac{3}{4})}^{2} ⎤ ⎦}^{2} ∵ a^{- m} = \frac{1}{a^{m}}$
$= {[{(\frac{3}{4})}^{2} - {(\frac{3}{4})}^{2}]}^{2}$
$= 0$